Question

Two solutions of differently concentrations of acid are mixed creating 40 mL of a soul union that is 32% acid one-quarter of the soulutiob is made up of 20% acid soulution. The remaining three quarters is made up of a solution of unknown concentration c. Which equation can be used to determine c, the unknown.

Answer 1

Answer: Three quarters (30 ml) is made up of a 36% acid solution.

Explanation:

Since we have given that

Total amount of solution = 40 ml

One- quarter of the solution is given by

`(1)/(4)* 40\ ml\\\\=10\ ml`

Three-quarter of the solution is given by

`(3)/(4)* 40\\\\=30\ ml`

According to question, we have

10 ml of solution is made up of = 20% of acid solution

30 ml of solution is made up of = say 'c ' of acid solution

40 ml of solution is made up of = 32 % of acid solution

So, our equation becomes,

`10* 0.2+30* c=40* 0.32\\\\2+30c=12.8\\\\30c=12.8-2\\\\30c=10.8\\\\c=(10.8)/(30)\\\\c=0.36\\\\c=36\%`

Hence, three quarters (30 ml) is made up of a 36% acid solution.