Question

Helpppp know!!!! It’s math and it is genmontry

Answer 1

Part 7) Adjacent angles

m<SUR and m<RUN

m<TUP and m<PUQ

Part 8) Vertical acute angles

m<SUR and m<PUQ

m<RUN and m<TUP

Part 9) Supplementary angles

m<SUT and m<TUQ

m<SUR and m<QUR

Part 10)
`m<QUR=139\°`

Part 11) m<RUQ is greater than m< TUR

Part 12)
`x=21\°`

Part 13)
`m<KMH=96\°`

Explanation:

Part 7) we know that

we know that

Two angles are Adjacent when they have a common side and a common vertex

In this problem

m<SUR and m<RUN ----> are adjacent angles

because have a common side UR and a common vertex U

m<TUP and m<PUQ ----> are adjacent angles

because have a common side UP and a common vertex U

Part 8) we know that

An angle is acute when is measure is less than
`90` degrees

Vertical Angles are the pair of congruent angles opposite each other when two lines cross

In this problem

`m<SUR=m<PUQ=41\°` ------> by vertical angles

`m<RUN=m<TUP=49\°` ------> by vertical angles

Part 9) we know that

Two angles are supplementary if its sum is equal to
`180` degrees

In this problem

`m<SUT+m<TUQ=180\°` ------> by supplementary angles

`m<SUR+m<QUR=180\°` ------> by supplementary angles

Part 10) Find m<QUR

we know that

`m<SUR+m<QUR=180\°` ------> by supplementary angles

we have

`m<SUR=41\°`

substitute

`41\°+m<QUR=180\°`

`m<QUR=180\°-41\°=139\°`

Part 11) which is greater m<TUR or m< RUQ

we know that

m<TUR=m<TUS+m<SUR

substitute the values

`m<TUR=90\°+41\°=131\°`

`m<RUQ=m<QUR=139\°` ----> see the procedure problem 10

therefore

m<RUQ is greater than m< TUR

Part 12) Find the measure angle x

`4x=84\°` ------> by vertical angles

solve for x

`x=84\°/4=21\°`

Part 13) m<KMH

we know that

`m<KMH+84\°=180\°` -----> by supplementary angles

`m<KMH=180\°-84\°=96\°`