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Find the mass in grams of hydrogen gas produced when 14.0 moles of HCl is added to an excess amount of magnesium.

User Ewoks
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1 Answer

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Answer;

14.0 g of hydrogen gas

Explanation;

The equation for the reaction is

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)

From the equation, 2mol HCl will produce 1 mol H2

Moles of HCl =14 moles

Therefore; 14 moles of HCl will produce 7 moles of hydrogen gas

1 mole of Hydrogen gas = 2.0 g/mol

Thus; mass of 7.0 moles of H2 = 7 × 2.0 g/mol

= 14.0 g

User Raphael K
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