Question

A 12-kg bag of groceries is tossed onto a table at 4.0 m/s and slides to a stop in 2.2 s .

Modify the equation FΔt=Δ (mv) to find the force of friction.

Answer 1

The force of friction can be found using the equation FΔt = Δ(mv), where F is the force of friction, Δt is the change in time, and Δ(mv) is the change in momentum. Plugging in the given values, we find that the force of friction is 21.82 N.

Step-by-step explanation:

To find the force of friction, we can use the equation FΔt = Δ(mv). In this case, the initial velocity of the bag is 4.0 m/s, the final velocity is 0 m/s (since it slides to a stop), and the change in time is 2.2 s. The mass of the bag is 12 kg. Plugging these values into the equation, we get F(2.2) = 12(0 - 4). Solving for F, we get F = (-12 * -4) / 2.2 = 21.82 N.

Answer 2

As we know that bag is stopped due to the force of friction on the table

so here by the given equation we will say

`F\Delta t = \Delta (mv)`

now we have

`F = (\Delta (mv))/(\Delta t)`

now from the above equation we also have

`F = ((mv)_f - (mv)_i)/(\Delta t)`

now we have

`v_f = 0`

`v_i = 4 m/s`

m = 12 kg

`\Delta t = 2.2 s`

now we will have

`F = (0 - (12)(4))/(2.2)`

`F = -21.82 N`

so friction force will be 21.82 N