100k views
1 vote
Find the area of a parallelogram with the given vertices. P(-2, -5), Q(9, -5), R(1, 5), S(12, 5)

User Mtekeli
by
5.2k points

1 Answer

3 votes

Answer:

The area of the parallelogram is 55 square unit.

Explanation:

The area of a parallelogram is


A=(1)/(2)* base* height

It is given that the vertices of the parallelogram are P(-2, -5), Q(9, -5), R(1, 5), S(12, 5).

Plot these points on a coordinate plane, and draw a perpendicular on PQ from the point R.

From the graph is clear that length of PQ is 11 and the height of the parallelogram is 10. So, the area of a parallelogram is


A=(1)/(2)* 11* 10


A=55

Therefore the area of the parallelogram is 55 square unit.

Find the area of a parallelogram with the given vertices. P(-2, -5), Q(9, -5), R(1, 5), S-example-1
User Sacha Barber
by
6.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.