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Solve the equation for Imaginary Numbers 1/2(x^2+40)=-12

User Richardgirges
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1 Answer

23 votes
23 votes

Answer:

8i and -8i

Explanation:

Move everything into the left-hand side to get a quadratic equation:


(1)/(2)(x^2+40)=-12\\(1)/(2)x^2+20=-12\\(1)/(2)x^2+32=0

Solve for x using the quadratic formula:


(1)/(2)x^2+32=0\\x=(-b\±√(b^2-4ac))/(2a)\\x=\frac{-(0)\±\sqrt{0^2-4((1)/(2))32}}{2((1)/(2))}\\x=\±√(-64)\\x=\±8i

The two imaginary solutions for the equation are 8i and -8i.

User Laogeodritt
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