Question

When a 5.0kg cart undergoes a 2.2m/s increase in speed, what is the impulse of the cart

Answer 1

In this question we have given

mass of Cart=5Kg

change in speed,
`\Delta v=2.2(m)/(s)`

We have to find, Impulse, I=?

Impulse :

Impulse of a body is equla to its change in momentum.

Therefore,

Impulse of cart is equal to its change in momentum:

`I=\Delta p\\I=m\Delta v`................(1)

Put values of
`\Delta v`, and m in eq(1)

`I=(5.0kg)(2.2(m)/(s) )\\I=11 kg(m)/(s)`

Therefore, the impulse of the cart,
`I=11 kg(m)/(s)`

Answer 2

11.0 kg m/s

Step-by-step explanation:

The impulse exerted on the cart is equal to its change in momentum:

`I=\Delta p=m\Delta v`

where

m = 5.0 kg is the mass of the cart

`\Delta v=2.2 m/s` is its change in speed

Substituting numbers into the equation, we find

`I=(5.0kg)(2.2 m/s)=11 kg m/s`