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When a 757 passenger jet begins its descent to the Ronald Reagan National Airport in Washington, D.C., it is 3900 feet from the ground. Its angle of descent is 6 degrees.

How far must the plane fly to reach the run way?
A. 37,106 ft
B. 37,310.4 ft
C. 23,456.6 ft
D 2,492.7 ft

User DanEEStar
by
4.8k points

2 Answers

1 vote

Answer:

D

Explanation:

User Steoates
by
5.0k points
3 votes

Answer:

Option A. 37106 ft.

Explanation:

Given: An 757 passenger jet at the height of 3900 feet from the ground means vertical height = 3900 feet.

Angle of descent to the airport in Washington,D.C. is 6 degrees.

To find: Horizontal distance the plane will cover to reach the run way.

Solution: As we know tan ∅ =
(Height)/(Base)

Then tan 6° =
(3900)/(x)

0.105 =
(3900)/(x)

x =
(3900)/(.105)

x = 37106 ft

User UDKOX
by
5.6k points
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