Question

How many times larger is 9 × 10^8 than 3 × 10^-5?

A. 3 × 10^13
B. 3 × 10^-40
C. 3 × 10^-13
D. 3 × 10^3

Answer 1

A. 3 × 10¹³

Explanation:

We have the numbers, 9 × 10⁸ than 3 × 10⁻⁵.

To find the factor by which 9 × 10⁸ is greater by 3 × 10⁻⁵ is given by,

`(9* 10^(8))/(3* 10^(-5))`

i.e.
`\frac{3* 10^(8+5)}`

i.e.
`\frac{3* 10^(13)}`

So, 9 × 10⁸ is 3 × 10¹³ times greater than 3 × 10⁻⁵.

i.e. 3 × 10⁻⁵ × 3 × 10¹³ = 3 × 3 × 10⁻⁵⁺¹³ = 9 × 10⁸.

Hence, option A is correct.