Question

Urgent question in Mathematics. Solve this to get 15 points


`{2}^(100) - {2}^(99) - {2}^(98) .... {2}^(2) - {2}^(1) - {2}^(0)`
a) 0
b) 1
c) 2
d) 2^50

Answer 1

the correct answer is B

Answer 2

1.

Explanation:

Note that 2^4 - 2^3 = 16 - 8 = 8 = 2^3

In a similar way 2^6 - 2^5 = 64 - 32 = 32 = 2^5.

So 2^99 - 2^98 = 2^98 , 2^98 - 2^97 = 2^97 , 2^97 - 2^96 = 2^96 and so on.

Therefore when we come to the last 2 terms we have 2^1 - 2^0 = 2 - 1

= 1 , so the answer is 1.