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16 min left need help asap

16 min left need help asap-example-1
User BiTOk
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1 Answer

5 votes

Answer: XD < XY

Explanation:

Since, By the exterior angle property,


\angle DXY + \angle DYX = 98^(\circ)

Since, given,
\angle DXY = 46^(\circ)

Therefore,
46^(\circ) + \angle DYX = 98^(\circ)


\angle DYX = 52^(\circ)

Now,
\angle YDX = 180^(\circ)-98^(\circ)= 82^(\circ) ( by the property of linear angles )

Thus,
\angle DYX < \angle YDX

Since, In a triangle, the opposite side of largest angle is always greater than that of smallest angle.

XD < XY

Hence, Option C is correct.

User Nschum
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