Answer:
Option C, An electron in the 3 p orbital of the third electron shell has more potential energy than an electron in the 2 p orbital of the second electron shell.
Step-by-step explanation:
There are different arrangements of orbits s,p,d and f, where s is the closest to the nucleus and has least energy as compared to other orbits. Also, even in p orbitals an electron which lies in 2p orbit is close to nucleus and hence has less energy as compared to electron lying in 3p orbit. Thus, the nearer the orbit lies to the nucleus , the lesser is the energy of the electron rotating in this orbit as they face the strongest force of positively charged nucleus.
Hence, option C is correct.