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What is the equation of a circle whose radius is 16 units and center is at (2,-5)?

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Answer:

  • The general equation of the circle is

  • ( {x - a})^(2) + ({y - b})^(2) = {r}^(2) \\ therefore \: we \: \: have \: \\ ( {x - 2})^(2) + (y - ( - 5)) {}^(2) = ({16})^(2) \\ ({x - 2})^(2) + ( {y + 5})^(2) = 256
  • HOPE THIS HELPS!
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