Ans: The sign of the slope is negative
The free energy change (ΔG) is related to the equilibrium constant Kp as:
ΔG = -RTlnKp -------(1)
Also, ΔG = ΔH-TΔS ------(2)
therefore,
-RTlnKp = ΔH-TΔS
ln(Kp) = -ΔH/R(1/T) + ΔS/R
Thus, a plot of lnKp Vs 1/T will give a straight line with a negative slope such that:
Slope = -ΔH/R
Intercept = ΔS/R