Answer:
1. A. Graph below
1. B. Trapezoid
2. Interior angles are 63.3°, 147.9°, 27.13° and 121.6°.
Explanation:
Ques 1: We are given that, for quadrilateral CONR,
CO is represented by the line
when

RN is represented by the line
when

Part A). After plotting the lines, we will get the following graph.
Part B) Joining the end points, we see that, CONR is a trapezoid.
Ques 2: Since, we know,
The sum of the interior angles of a quadrilateral is 360°
So, we have,

i.e.

i.e.

i.e.

i.e.

i.e.

i.e. x= 63.3°
So, we have,
x= 63.3°
(3x-42)° = (3×63.3 - 42)° = (189.9-42)° = 147.9°
= 27.13°
(2x-5)° = (2×63.3-5)° = (126.6-5)° = 121.6°
Thus, the interior angles are 63.3°, 147.9°, 27.13° and 121.6°.