54.5k views
3 votes
What is the equation of a line that is perpendicular to the given line and has an x-intercept of 6?

User Rodriguez
by
8.4k points

2 Answers

3 votes

Answer:

C.

Explanation:

Just took the test ;)

User CLo
by
7.6k points
3 votes

Answer:

y = 4/3(x) - 8

Explanation:

First we have to find the equation for the given line (I use y = mx + b for everything, although I think it can be done with other formats). The equation for slope is (y2 - y1)/(x2 - x1) = m, so we'll start with that.

(-2 - 4) / (4 - (-4)) = m

-6 / 8 = m

m = -3/4

Now, let's find the rest of the equation. We can do this by treating b as the unknown variable it is, and plugging in a known xy pair, then simply solving for the unknown variable.

y = mx + b; y = 4, x = -4, m = -3/4

4 = -4(-3/4) + b

4 = 3 + b

b = 1

Now we have the original line's equation, y = -3/4(x) + 1. We need to find the new line's slope by finding the negative reciprocal of the base line's. For that, we simply flip the numerator and denominator, then multiply it by -1, to get 4/3. Now we find b again, using the point (6, 0).

y = mx + b; y = 0, x = 6, m = 4/3

0 = 4/3(6) + b

0 = 8 + b

b = -8

This makes our final answer y = 4/3(x) - 8.

User Tallowen
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories