Question

What is the area of the figure?

a 28 yd

b 40 yd

c 52 yd

d 64 yd

Answer 1

b

Explanation:

The figure is composed of a square and a right triangle

area of a square = s² ( s is the length of a side )

area of triangle =
`(1)/(2)` bh ( b is the base and h the height )

Total area = 4² + ( 0.5 × 6 × 8 ) = 16 + 24 = 40 yd² → b

Answer 2

b. 40 yd²

Explanation:

We have the square and the right triangle.

The formula of an area of a square:

`A_{\boxed{}}=a^2`

a - length of side

The formula of an area of a right triangle:

`A_\triangle=(ab)/(2)`

a,b - legs

We have:

SQUARE:

a = 4 yd

`A_{\boxed{}}=4^2=16\ yd^2`

RIGHT TRIANGLE:

a = 6 yd, b = 4 yd + 4 yd = 8 yd

`A_\triangle=((6)(8))/(2)=(3)(8)=24\ yd^2`

The area of the figure:

`A=A_{\boxed{}}+A_\triangle\\\\A=16\ yd^2+24\ yd^2=40\ yd^2`