Answer:
0.44 g/L.
Step-by-step explanation:
- This problem is an application on Henry's law.
- Henry's law states that the solubility of a gas in a liquid is directly proportional to its partial pressure of the gas above the liquid.
- Solubility of the gas ∝ partial pressure
- If we have different solubility at different pressures, we can express Henry's law as:
- S₁ = 1.22 g/L and P₁ = 2.75 atm
- S₂ = ??? g/L and P₂ = 1.0 atm
- So, The solubility of the gas at 1.0 atm (S₂) = S₁.P₂/P₁ = (1.22 g/L x 1.0 atm) / (2.75 atm) = 0.44 g/L.