Answer:
The value at the end of year 2 is $4400.
Explanation:
The best approach here is to determine the expression for the line depreciation and then calculate the depreciation value at x = 2 years.
A line is given by
![y = mx + b](https://img.qammunity.org/2020/formulas/mathematics/high-school/fc4cgm6covys37zv2opmmp9ps4jxyjepvh.png)
where m is the slope and b the bias (aka y-intercept). You can determine both directly from what is given. The slope is change in y divided by change in x. We know that over 5 years the car loses (500-7000)=-6500 in value. So, the slope is m=-6500/5 (note the negative sign). At time 0, the y-intercept is 7000, since that is the initial value (at year 0). So our line function is fully identified:
![y = -(6500)/(5)x+7000](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3yla2749eoyc7pnq6199hsq8834b67ozqk.png)
and gives you the value of the car in any given year. To answer the question, we now plug in 2 as value of x:
![y=-(6500)/(5)\cdot 2 + 7000= 4400](https://img.qammunity.org/2020/formulas/mathematics/middle-school/o07ogk531r7uqogu1zthnz97hh8gdb9fzv.png)