Question

How many ammonium ions and how many sulfate ions are present in a 0.270 mol sample of ?

Answer 1

Answer: There are
`3.25188* 10^(23)` ammonium ions and
`1.62594* 10^(23)` sulfate ions in the given amount of ammonium sulfate.

Step-by-step explanation:

We are given 0.270 moles of ammonium sulfate and we need to find the number of ammonium and sulfate ions in it. The equation for the ionization of ammonium sulfate is given by the reaction:

`(NH_4)_2SO_4\rightarrow 2NH_4^++SO_4^(2-)`

By Stoichiometry,

1 mole of ammonium ions dissociates into 2 moles of ammonium ions and 1 mole of sulfate ion.

According to the mole concept:

1 mole of an ionic compound contains
`6.022* 10^(23)` number of ions.

Hence, 0.270 mole of ammonium sulfate will contain
`0.270* 2* 6.022* 10^(23)=3.25188* 10^(23)` number of ammonium ions and
`0.270* 1* 6.022* 10^(23)=1.62594* 10^(23)` number of sulfate ions.

Hence, there are
`3.25188* 10^(23)` ammonium ions and
`1.62594* 10^(23)` sulfate ions in the given amount of ammonium sulfate.