Question

Solve the rational equation

and check for extraneous solutions

5 = 4x+1
— ——-
x x^2

(1) x= 1; x = 0 is an extraneous solution

(2) x=0; x = 1 is an extraneous solution

(3) x= -1; x = 0 is an extraneous solution

(4) x=0; x = -1 is an extraneous solution

Answer 1

1) x=1; x= 0 is an extraneous solution

Explanation:

5 = 4x + 1

5 = 4 x 1 + 1

5 = 5

x = 1

______________________

x x^2

0 x 0^2

0 x 0 = 0

x = 0

:)