Question

The average test scores for a particular test in algebra was 84 with a standard deviation of 5. What percentage of the students scored higher than 89%? Please explain your answer.

Answer 1

The percentage of the students scored higher than 89% is 15.87%

Explanation:

we are given

The average test scores for a particular test in algebra was 84

so, mean is 84

`\mu=84`

a standard deviation of 5

so,

`\sigma=5`

we have

x=89

now, we can use z-score formula

`z=(x-\mu)/(\sigma)`

now, we can plug values

`z=(89-84)/(5)`

`z=1`

now, we can use calculator

and we get

`p(z>1)=0.1587`

So,

The percentage of the students scored higher than 89% is 15.87%