Answer:
42
Explanation:
Perimeter of quadrilateral with inscribed circle:
Two tangents from a point outside the circle to some point to a circle are of equal lengths.
CB = 3+ 5 = 8
CD = 3+ 4 = 7
DA = 4 + 9 = 13
AB = 9+ 5 = 14
Perimeter = 8 + 7 + 13 + 14
= 42