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How many solutions are there on the equation below 16(x+2)-8=16x+24

User NessDan
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1 Answer

6 votes

Answer:

Infinitely many solutions

Explanation:

First,


16(x+2)=16\cdot x+16\cdot 2=16x+32.

Then


16(x+2)-8=16x+32-8=16x+24.

The equation becomes


16x+24=16x+24.

This equation is always true equality (because left and right parts are the same for all possible values of x). This means that equation has infinitely many solutions.

User Amrit
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