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Quadrilateral ABCD is drawn on a coordinate plane. Find the length of the side AB. Please help

Quadrilateral ABCD is drawn on a coordinate plane. Find the length of the side AB-example-1

2 Answers

4 votes

Hello from MrBillDoesMath!

Answer:

sqrt(45)


Discussion:

See the attached file. The length AB is the hypotenuse of the right triangle with sides 3 and 6. Hence


AB = sqrt ( 3^2 + 6^2)

= sqrt ( 9 + 36 )

= sqrt (45) <----- this is the answer they wanted!

= sqrt (9 *5)

= sqrt(9) * sqrt(5)

= 3 * sqrt(5)


Thank you,

MrB

Quadrilateral ABCD is drawn on a coordinate plane. Find the length of the side AB-example-1
User Dave Moten
by
4.1k points
3 votes

Answer:

B. /AB/ =
√(45) units

Explanation:

A quadrilateral is the class of four sided figures. Examples include: squares, rectangles, rhombus, kite, parallelogram, trapezium etc.

From the graph, the quadrilateral is in the form of a trapezium.

the length of the side AB can be determined by:

Draw a perpendicular from B to meet AD at E to form triangle ABE,

From triangle ABE, AE = 3 units and BE = 6 units. Applying the Pythagoras theorem to determine the length AB, we have;


/AB/^(2) =
/BE/^(2) +
/AE/^(2)

=
6^(2) +
3^(2)

= 36 + 9


/AB/^(2) = 45

Find the square root of both sides,

/AB/ =
√(45)

Thus,

/AB/ =
√(45) units

User Bitclaw
by
4.5k points