81.3k views
5 votes
A reaction in which a, b, and c react to form products is zero order in a, one-half order in b, and second order in

c. by what factor does the reaction rate change if the concentration of a is doubled? 1 by what factor does the reaction rate change if the concentration of b is doubled? 1.4 by what factor does the reaction rate change if the concentration of c is doubled? 4

User Aqeel
by
5.7k points

1 Answer

4 votes

Answer: a) 1

b) 1.414

c) 4

Step-by-step explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.


A+B+C\rightarrow products


Rate=k[A]^0[B]^(1)/(2)[C]^2

a)
Rate^'=k[2A]^0[B]^(1)/(2)[C]^2


Rate^'=k[2]^0[A]^0[B]^(1)/(2)[C]^2


Rate^'=1* Rate

b)
Rate^'=k[A]^0[2B]^(1)/(2)[C]^2


Rate^'=k[A]^0[2]^(1)/(2)[B]^(1)/(2)[C]^2


Rate^'=[2]^(1)/(2)Rate


Rate^'=1.414* Rate

c)
Rate^'=k[A]^0[B]^(1)/(2)[2C]^2


Rate^'=k[A]^0[B]^(1)/(2)[2]^2[C]^2


Rate^'=[2]^2Rate


Rate^'=4* Rate




User TidB
by
5.9k points