Question

In the picture thank you

Answer 1

The correct answer is b) 1100 adults and 1400 students.

Explanation:

To find this, set up a system of equations in which x is the number of students who attend and y is the number of adults who attend.

First start by creating an equation for money made.

5x + 10y = 18,000

Now write an equation for the amount that attend.

x + y = 2,500

Now multiply the bottom equation by -5 and add the equations together.

-5x - 5y = -12,500

5x + 10y = 18,000

5y = 5,500

y = 1,100

Since this is the number of adults, we can plug into an original equation to find the number of students.

x + y = 2,500

x + 1,100 = 2,500

x = 1,400

Answer 2

1100 adults and 1400 students

Explanation:

Let S = students and A = adults.

We have two conditions.

(1) 5S + 10A = 18 000

(2) S + A = 2500 Subtract A from each side

(3) S = 2500 – A Substitute (3) into (1)

5(2500 – A) + 10A = 18 000 Remove parentheses

12 500 – 5A + 10 A = 18 000 Combine like terms

12 500 + 5A = 18 000 Subtract 12 500 from each side

5A = 5500 Divide each side by 6

(4) A = 1100 Substitute (4) into (2)

S + 1100 = 2500 Subtract 1100 from each side

S = 1400

There were 1100 adults and 1400 students.

Check:

5 × 1400 + 10 × 1100 = 18 000 1400 + 1100 = 2500

7 000 + 11 000 = 18 000 2500 = 2500

1 8 000 = 18 000