Question

Using the quadratic formula -3x^2+36x=0 to solve, what are the values for a, b and c

Answer 1

`a=-3\\b=36\\c=0`

Explanation:

The values of a, b, c, are:

• a is whatever is in front of
  `x^2` term (including sign)
• b is whatever is in front of
  `x` term (including sign)
• c is the constant term (including the sign)

So for
`-3x^2+36x=0`, we clearly see that a is -3, b is 36, and since there is no constant term, c is 0