Electric field between the plates of capacitor is given by
![E = (Q)/(A\epsilon_0)](https://img.qammunity.org/2020/formulas/physics/college/avpqwo860a1dp2uar5lgecy585kax8jobp.png)
potential difference between the plates of capacitor is given by
![V = E.d](https://img.qammunity.org/2020/formulas/physics/college/e4hiulmp2w7qyd0pajm15wjbv2r5h9sbzd.png)
![V = (Qd)/(A\epsilon_0)](https://img.qammunity.org/2020/formulas/physics/college/j7mn4eigz588bzoir5tcwpdmmqp1zpyvyu.png)
so above two parameters will depend on the charge of capacitor
rest we know that capacitance of capacitor is given as
![C = (\epsilon_0 A)/(d)](https://img.qammunity.org/2020/formulas/physics/college/o2fpqecg3r13r7edm3jinp8hrn9lcgg3gp.png)
so it is independent of charge
so correct answer will be
The electric field across the plates.
The potential across the plates.