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Write a linear equation in standard form given the line passes through (-4,-3) and (6,-2).

User Thepeanut
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1 Answer

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(-2+3)/(6+4)= 1/10

y+3=1/10(x + 4)

y + 3 = (1/10)x + 4/10

y + 30/10 = ( 1/10)x + 4/10

y = (1/10)x + 4/10 - 30/10

y = (1/10)x - 26/10

y = (1/10)x - 13/5

10(y = (1/10)x - 13/5)

10y = x - 26

-x + 10y = -26

User Michael Wyraz
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