Question

the average adult male can hold about 3 liters of air. how many moles of air can the lung hold at a pressure of 500 kPa and temperature of 310 k

Answer 1

Answer: 0.58 moles

Explanation: Using ideal gas equation:

PV = nRT

`n=(PV)/(TR)`

P= pressure =500 kPa=4.93 atm [1 kPa= 0.009atm]

V= volume =3 L

n = no of moles = ?

R= gas constant =0.0821 Latm\molK

T= temperature = 310K

`n=(4.93* 3)/(310* 0.0821)=0.58moles`