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A chemist determined by measurements that 0.015 moles of iron participated in a chemical reaction. Calculate the mass of iron that participated in the chemical reaction. Round your answer to 2 significant digits.

1 Answer

1 vote

Answer: 0.84 g

Step-by-step explanation:


\text{ Mass of iron}=\text{ Moles of iron}* \text{ Molar mass of iron}

Given: moles of iron = 0.015

Molar mass of iron = 56 g/mol


\text{ Mass of iron}=0.015* 56g/mol=0.84g

Thus 0.84 g of iron participated in the chemical reaction.

User Joaquin Brandan
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