Answer:
(y^2+5y+25)
Explanation:
(y^3 - 125) ÷ (y -5)
Factor the first term. This is the difference of cubes
a^3 – b^3 = (a – b)(a^2 + ab + b^2)
Let a=y and b = 5 (5^3 =125)
(y^3-125) = (y-5) (y^2+5y+25)
Substitute this back into the original equation
(y-5) (y^2+5y+25)
----------------------------
(y-5)
The y-5 term cancels
(y^2+5y+25)