Question

What is the equation of the line, in point-slope form, that passes through the points (9,1) and (4,16)

Answer 1

y-1 = -3(x-9)

Explanation:

First we need to find the slope

m = (y2-y1)/(x2-x1)

= (16-1)/(4-9)

= 15/-5

= -3

Then we can use point slope form to make an equation for the line

y-y1 = m(x-x1)

y-1 = -3(x-9)

We could also use the other point

y-16 = -3(x-4)