Question

The admission fee at an amusement park is $ 1.25 for children and $ 6.00 for adults. On a certain day, 391 people entered the park, and the admission fees collected totaled $ 1415 . How many children and how many adults were admitted?

There were ___________ children admitted.

There were _____________ adults admitted

Answer 1

196 children

195 adults

Explanation:

x---> children

y---> adults

Set up sistem of equations:

x + y = 391

1.25x + 6y = 1415

By substitution:

x = 391 - y

1.25(391 - y) + 6y = 1415

6y - 1.25y = 1415 - 488.75

y = 926.25/4.75 = 195 adults

x = 391 - 195 = 196 children

Answer 2

196 children, 195 adults

Explanation:

Use a for adults and c for children

a + c = 391

6a + 1.25c = 1415

Rearrange the first equation to be one variable alone:

a = 391 - c, then replace a in the second equation with that

6(391 - c) + 1.25c = 1415

2346 - 6c + 1.25c = 1415

2346 - 4.75c = 1415

-4.75c = -931

c = 196

There were 196 children admitted.

Now replace that into the original equation:

a + 196 = 391

a = 195 195 adults attended