Answer: The entangled players would move with a speed of 0.2 m/s in the direction direction of the motion of second soccer player.
Step-by-step explanation:
From law of conservation of momentum,
Initial momentum of the closed system = final momentum of the closed system
Since, no external force is acting on the players, total momentum would be conserved.
m₁u₁+m₂u₂=(m₁+m₂)v
where, m₁ is the mass of one soccer player = 40 kg
u₁ is its initial velocity before collision = 4 m/s
m₂ is the mass of the other soccer player = 60 kg
u₂ is the initial velocity before collision = - 3 m/s (∵opposite direction)
After collision, the two players get entangled and hence move with the same final velocity v.
40 kg × 4 m/s - 60 kg × 3 m/s = (40 kg + 60 kg ) v
160 kg m/s - 180 kg m/s = 100 kg v
v = -0.2 m/s
Hence, the entangled players would move with a speed of 0.2 m/s in the direction direction of the motion of second soccer player.