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10 votes
10 votes
Using the quadratic formula to solve 5x = 6x²-3, what are the values of x?

User Atulmy
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1 Answer

15 votes
15 votes

Answer:


\boxed{\sf{x = (5 \pm √(97) )/(12) }}

Explanation:


\sf{5x = 6 {x}^(2) - 3 }


\sf{0 = 6 {x}^(2) - 3 - 5x }


\sf{0 = 6 {x}^(2) - 5x - 3 }

  • a = 6
  • b = - 5
  • c = - 3


\sf{x = \frac{ - b \pm \sqrt{ {b}^(2) - 4ac} }{2a} }


\sf{x = \frac{ - ( - 5) \pm \sqrt{ { - 5}^(2) - 4(6)( - 3)} }{2(6)} }


\sf{x = (5 \pm √( 25 + 72) )/(12) }


\sf{x = (5 \pm √(97) )/(12) }

User Kieran Hunt
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