Question

Make tables to find the solution to 4^−x = 2^x + 3. Take the integer values of x between −3 and 3.

Answer 1

the solution is at -1 which is 4.

Explanation:

We have been given two functions:

`4^(-x)\text {and} 2^(x+3)`

We need to take x between -3 and 3

x
`y_1=4^(-x)`
`y_2=2^(x+3)`

-2 16 2

-1 4 4

0 1 8

1 1/4 16

2 1/16 32

Solution is that point where these two function will give same value.

So, the solution is at -1 which is 4.