Question

(9x^3-6x^2+3x)/3x

Can someone help me pls ı know the answr is 3x^2-2x+1 but ı cant understand ı just need some one to explain me

Answer 1

By the distributive property of multiplication,

`(9x^3-6x^2+3x)/(3x)=(9x^3)/(3x)-(6x^2)/(3x)+(3x)/(3x)`

(you're multiplying
`9x^3-6x^2+3x` by
`\frac1{3x}`)

Then cancel common terms that appear in the numerator and denominator - if
`a\\eq0`, then
`\frac aa=1`.

`(9x^3)/(3x)-(6x^2)/(3x)+(3x)/(3x)=(3x^2\cdot3x)/(3x)-(2x\cdot3x)/(3x)+(3x)/(3x)=3x^2-2x+1`