Question

A photon that has an energy of 8.63 × 10^-12 J would emit light at which wavelength (pm)

Answer 1

Answer:The photon will emit light of
`2.30* 10^(-2) pm`.

Step-by-step explanation:

The energy emitted by the photon,E :
`8.63* 10^(-12) J`

Wavelength of the light emitted by this photon =
`\lambda`

`E=(hc)/(\lambda )`

h = Planck's constant =
`6.626* 10^(-34) Js`

c = speed of the light =
`3* 10^(8) m/s`

`8.63* 10^(-12) J=(6.626* 10^(-34) Js* 3* 10^(8) m/s)/(\lambda )`

`\lambda=(6.626* 10^(-34) Js* 3* 10^(8) m/s)/(8.63* 10^(-12) J)=2.30* 10^(-14) m=2.30* 10^(-2) pm`

`1 m=1* 10^(12) pm`

The photon will emit light of
`2.30* 10^(-2) pm`.