Answer:
2a
Explanation:
to factor 18a, 20ab, and 6ab, first you'd have to figure out which variable could be factor-able between these three terms. since 18a does not contain a b, but all the terms of a, you can safely assume that a is factorable. next you have to find a number that is a common factor of 18, 20, and 6. we can begin from 6 since it's the lowest number, but since it isn't a factor of all three, the factor would not be six. as you count down the list and rule each out (5,4,3) the only number that is a common factor between all these terms is 2.
so your answer is 2a.
2a(9) = 18a
2a(10b) = 20ab
2a(3b) = 6ab
Answer: 2a
Step-by-step explanation:
18a: 1,2,3,6,9,18 then there's A
20ab: 1,2,4,5,10,20 then there's A and B
6ab: 1,2,3,6 then there's A and B
All have a 2 and an A in common so it's 2a
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