Answer: 21y^5-28y^4+49y^3
If the remainder isn't necessarily zero, we add C_1y^2+C_2y+C_3, which covers all possible remainders when dividing by a polynomial with leading term in y^3.
Explanation:
(3y^2-4y+7)(7y^3) =
21y^5-28y^4+49y^3
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