Answer:
This series is convergent
(A)
Explanation:
We are given a series
Firstly, we will find nth term
So, numerator is
![=2n+1](https://img.qammunity.org/2020/formulas/mathematics/high-school/p52coxt5w79vnun0k67wia2pa5d0rej1h5.png)
So, denominator is
![=n!](https://img.qammunity.org/2020/formulas/mathematics/high-school/2booruth86w8zylanhssdhtxl5t90x2ld1.png)
so, nth term will be
![a_n=(2n+1)/(n!)](https://img.qammunity.org/2020/formulas/mathematics/high-school/jsyt6vnshgopykpuvgxvf0c87r7kwatmas.png)
now, we can use ratio test
![L= \lim_(n \to \infty) (a_n_+_1)/(a_n)](https://img.qammunity.org/2020/formulas/mathematics/high-school/pt4j9fsx4qudb3vajgqm7t1iwohrximnxn.png)
![L= \lim_(n \to \infty) ((2n+3)/((n+1)!))/((2n+1)/(n!))](https://img.qammunity.org/2020/formulas/mathematics/high-school/6vzhfwqqdv8alslptv2us48d7c681v1wjk.png)
![L= \lim_(n \to \infty) (2n+3)/(\left(n+1\right)\left(2n+1\right))](https://img.qammunity.org/2020/formulas/mathematics/high-school/6x7q4qp3zwk15w836u62x4b4rckh26omib.png)
Since, denominator has two n terms
so, we get
![L=0<1](https://img.qammunity.org/2020/formulas/mathematics/high-school/zrs8wm4b2hobyj41y1yr8vuq44ksi8w17d.png)
So, this series is convergent