Answer:
Triangle is isosceles
Explanation:
Isosceles triangle is a triangle in which two sides are equal. To identify the above triangle as isosceles or right we need to find the length of sides.
The length of line as shown in figure can be calculated for points A(x1,y1) and B(x2,y2) as:
length of a line=
![√((x2-x1)^2+(y2-y1)^2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nfczm4e6nctej3ztnzs7dhuhdhqee8lz7i.png)
As shown in figure of triangle, the three points are A(8,2), B(11,13) and C(2,6)
Length of AB=
![√((x2-x1)^2+(y2-y1)^2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nfczm4e6nctej3ztnzs7dhuhdhqee8lz7i.png)
=
![√((11-8)^2+(13-2)^2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kfyfsojnsnt0qvvlqye3x5jm3j8exvczuy.png)
=
=
![√(130)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tyn6mua2hsn3od1bo35pc8s0psl0t7lzia.png)
Length of AC=
![√((x2-x1)^2+(y2-y1)^2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nfczm4e6nctej3ztnzs7dhuhdhqee8lz7i.png)
=
![√((8-2)^2+(2-6)^2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jsa0anpsb5wd9y1eywxr7rbe83eqs8t090.png)
=
=
![√(52)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fknp33dtwve7uht3gutznhxmwtzxkix9km.png)
Length of BC=
![√((x2-x1)^2+(y2-y1)^2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nfczm4e6nctej3ztnzs7dhuhdhqee8lz7i.png)
=
![√((11-2)^2+(13-6)^2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/arpk4s7xjlocc1bl30mcof3x6i79pxuyum.png)
=
=
![√(130)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tyn6mua2hsn3od1bo35pc8s0psl0t7lzia.png)
AB=BC [As stated in condition above, two sides are same or equal ]
Therefore, we can see that the triangle is isosceles.