Question

Uranium-235 decays naturally, by alpha decay. Write the balance decay equation below

Answer 1

If all you are getting is Th then the balanced equation is written below

`_(92)^(235)\text{U} \longrightarrow _(90)^(231)\text{Th +}_(2)^(4)\text{He}`

The Uranium 235 decays into Thorium 231 and an alpha particle.

I'm not sure this decay happens in nature, but Uranium 238 does decay this way.

Answer 2

92U^235→90Th^231+2He^4

Step-by-step explanation

Uranium-235 produces thorium-231 by alpha decay.

An α-particle is a helium nucleus. It contains 2 protons and 2 neutrons, for a mass number of 4.

During α-decay, an atomic nucleus emits an alpha particle. It transforms (or decays) into an atom with an atomic number 2 less and a mass number 4 less.

Thus, uranium-238 decays through α-particle emission to form thorium-231

92U^235 → 90Th^231 + 2He^4