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Find the fifth term of a sequence whose first term is 8 and common ratio is 3/2

a.
81
b.
27/2
c.
81/2
d.
27


Please select the best answer from the choices provided

a) A
b) B
c) C
d) D

User Zeewagon
by
5.4k points

1 Answer

2 votes

Answer:

Option c. 81/2

Explanation:

Fifth term: a5=?

First term: a1=8

Common ratio: r=3/2

an=a1*r^(n-1)

with n=5

a5=a1*r^(5-1)

a5=a1*r^4

Replacing the known values:

a5=8*(3/2)^4

a5=8*(3)^4/(2)^4

a5=8*81/16

Simplifying: Dividing the numerator and denominator by 8:

a5=(8*81/8)/(16/8)

a5=81/2

Answer: Option c. 81/2

User Juan Lara
by
5.8k points