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Write a polynomial function of least degree with integral coefficients that has the given zeros. -1/3, 2/3, -1/4​

User Cool Goose
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1 Answer

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Explanation:

"integral" means here that the factors in the polynomial are integers.

we have 3 zeros.

the least degree of a polynomial with 3 zeros is 3.

and yes, that works also for 2 zeros (the degree must be at least 2, it must be at least a quadratic equation).

or 4 zeros (at least 4th degree).

it in general n zeros (at least nth degree).

constructing this out of the given zeros is easy.

what happens, when I multiply something by 0 ? the total result will be 0.

and so, we simply multiply 3 short terms with each other, where each term turns 0 for one of the given zeros.

what expression in x turns 0, when x = -1/3 ?

well : x + 1/3 or with integers 3x + 1 (multiplied by 3)

and for x = 2/3 ?

x - 2/3 or with integers 3x - 2

and for x = -1/4 ?

x + 1/4 or with integers 4x + 1

so, our polynomial function (of at least 3rd degree) is then

(3x + 1)(3x - 2)(4x + 1)

basically this could be already the result, depending on what your teacher wants.

for the fully extended form we need to do the multiplications :

(3x + 1)(3x - 2) = 9x² - 6x + 3x - 2 = 9x²- 3x - 2

(9x²- 3x - 2)(4x + 1) = 36x³ + 9x² - 12x² - 3x - 8x - 2 =

= 36x³ - 3x² - 11x - 2

the requested polynomial function is

f(x) = 36x³ - 3x² - 11x - 2

User Dominik Traskowski
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