Question

What is an equation in point-slope form of the line shown below?

Image is of a 2-dimensional graph with an x-axis and a y-axis. A line is passing through co-ordinate points (-4,1) and (4,-3).

A. y−1=−12(x+4)
B. y+3=2(x−4)
C. y−3=−12(x+4)
D. y+4=2(x+1)

Answer 1

Answer:

Hence, is the required equation of line.

Explanation:

A line is passing through the coordinates (-4,1) and (4,-3).

The equation of the line passing through () and () is given by:

Here we have: and

so on substituting in the formula we have:

Hence, is the required equation of line.

Explanation:

Answer 2

Hence,
`y-1=(-1)/(2)(x+4)` is the required equation of line.

Explanation:

A line is passing through the coordinates (-4,1) and (4,-3).

The equation of the line passing through (
`x_1,y_1`) and (
`x_2,y_2`) is given by:

`y-y_1=(y_2-y_1)/(x_2-x_!)(x-x_1)`

Here we have:
`(x_1,y_1)=(-4,1)` and
`(x_2,y_2)=(4,-3)`

so on substituting in the formula we have:

`y-1=(-3-1)/(4-(-4))(x-(-4))\\ \\y-1=(-4)/(8)(x+4)\\\\y-1=(-1)/(2)(x+4)`

Hence,
`y-1=(-1)/(2)(x+4)` is the required equation of line.