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1 vote
find the equation of the line passing through the given points. write the equation in slope-intercept form (1/5,-4) and (16/5,-9)

User Mfaani
by
6.7k points

2 Answers

7 votes

Answer:

y=
(-5)/(3)x
(-11)/(3)


Explanation:

y'-y1=m(x-x1)...........(1)

given

(x1,y1)=(
(1)/(5),-4)

(x2,y2)=(
(16)/(5),-9)

we know that slope=m=(
(y2-y1)/(x2-x1))

put values of (x1,y1) and (x2,y2)in above formula

we get

m=(
(y2-y1)/(x2-x1))

m=(
(-9-(-4))/(16/5-1/5))

m=(
(-9-+4))/(15/5))

m=(
(-5))/(15/5))

m=(
(-5))/(3))

now put slope (m) and points (x1,y1) in (1)

y-y1=m(x-x1)

y-(-4)=-5/3(x-1/5)

y+4= (-5/3)x+1/3

finally we get

y=
('-5)/(3)x+
(1)/(3)-4

y=
(-5)/(3)x
(-11)/(3)









User BobBrez
by
6.8k points
5 votes

Answer:


y=-(5)/(3)x-(11)/(3)

Explanation:

We need to write the equation in slope-intercept form which passes through points (1/5,-4) and (16/5,-9)

Slope is given formula:


m=(y_2-y_1)/(x_2-x_1)=(-9-\left(-4\right))/((16)/(5)-(1)/(5))=(-9+4)/((15)/(5))=(-5)/(3)

Now plug the value of slope m and any one of the given point into point slope formula:


y-y_1=m\left(x-x_1\right)


y-\left(-4\right)=(-5)/(3)\left(x-(1)/(5)\right)


y+4=-(5)/(3)x+(1)/(3)


y=-(5)/(3)x+(1)/(3)-4

Now simplify this and write in slope intercept form y=mx=b


y=-(5)/(3)x-(11)/(3)

Hence final answer is
y=-(5)/(3)x-(11)/(3)

User Jay Truluck
by
7.1k points