Question

For what values of b, the equation x^2−ax+b=0 has a solution for any value of a? PLEASE I NEED IT SOON!

Answer 1

If you choose
`b=0` the equation becomes

`x^2-ax = 0 \iff x(x-a) = 0`

which always has solutions
`x=0,\ x=a`

Answer 2

I’m not sure about the wording of the question, but wouldn’t it be all real numbers?